Posted by log on Thursday, July 2, 2009 at 7:49am.
4^(2x+1) * 7^(x-1) = 8^x * 14^2x
4^2x * 4 * 7^x /7 = (4*2)^x * (7^x)^2
(4/7)*(4^x)^2 = 4^x * 2^x * 7^x
(4/7)* 4^x = 2^x * 7^x
(4/7)* (2*2)^x = 2^x * 7^x = (14^x)
(4/7)*2^x = 14^x = (2*7)^x
(4/7) = 7^x
x log 7 = log (4/7) = -.559616
x = -.28758
14^x = 0.46816
Check my thinking. There may be a mistake along the way.
I used base e log to get x, but the base doesn't matter in this case.
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