you a framing a picture that is 5 in by 7in. with a 1 inch wide frame. find the perimeter of the outside edge of the frame. explain, pleaswe i know the anser is 32 but why?
5 + 2 = 7
7 + 2 = 9
P = 2L + 2W
P = 2(7) + 2(9)
P = 14 + 18
gracias!
but where does the 2 in five plus 2 come from?
The frame is on all sides.
To find the perimeter of the outside edge of the frame, we need to add up the lengths of all four sides of the frame.
The picture is 5 inches by 7 inches, and the frame has a uniform width of 1 inch all around. So, to find the dimensions of the frame, we need to subtract twice the width of the frame from both the length and the width of the picture.
The length of the frame (top and bottom) is the picture's length minus twice the width of the frame:
Length of frame = Length of picture - 2 * Width of frame
Length of frame = 7 inches - 2 * 1 inch
Length of frame = 7 inches - 2 inches
Length of frame = 5 inches
Similarly, the width of the frame (left and right) is the picture's width minus twice the width of the frame:
Width of frame = Width of picture - 2 * Width of frame
Width of frame = 5 inches - 2 * 1 inch
Width of frame = 5 inches - 2 inches
Width of frame = 3 inches
Now that we have the dimensions of the frame (5 inches by 3 inches), we can calculate the perimeter by adding up all four sides:
Perimeter of frame = 2 * (Length of frame + Width of frame)
Perimeter of frame = 2 * (5 inches + 3 inches)
Perimeter of frame = 2 * 8 inches
Perimeter of frame = 16 inches
However, since we are looking for the perimeter of the outside edge of the frame, we need to add the length of all four sides of the frame:
Perimeter of outside edge of frame = Perimeter of frame + 2 * Width of frame
Perimeter of outside edge of frame = 16 inches + 2 * 1 inch
Perimeter of outside edge of frame = 16 inches + 2 inches
Perimeter of outside edge of frame = 18 inches
Therefore, the perimeter of the outside edge of the frame is 18 inches.