for your birthday party, you make a map to your house on a 3-inch-wide by 5-inch-long index card.what will be the perimeter of your map if you use a copier to enlarge it so it is 8 inches long?
Please explain!:(
Your original map is 3 by 5.
3/5 =x/8
Solve for x, then 2x + 2(8) = perimeter
The perimeter is 4.8 becuase i did
8(3/5) that gives me 4.8. ALWAYS do image over pre-image..
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X=16 * 8/5 = 128/5 =25.6
Perimeter is 25.6
To find the perimeter of the enlarged map, we need to determine the length and width of the enlarged map.
Given:
Original map size: 3 inches wide by 5 inches long
Enlarged map length: 8 inches
To find the enlarged map width, we can use the ratio of the original length to the original width to determine how much the width should be scaled up. The original length to width ratio is 5:3.
So, for the enlarged map, we can set up a proportion:
(Original width) / (Original length) = (Enlarged width) / (Enlarged length)
Substituting the given values:
3 / 5 = (Enlarged width) / 8
Solving for the enlarged width:
(Enlarged width) = (3 / 5) * 8 = 24 / 5 = 4.8 inches
Now we know that the enlarged map's width is 4.8 inches, and its length is 8 inches.
To find the perimeter, we add up all the sides of the map:
Perimeter = 2 * (width + length)
Substituting the values we found:
Perimeter = 2 * (4.8 + 8) = 2 * 12.8 = 25.6 inches
Therefore, the perimeter of the enlarged map would be 25.6 inches.