The equation y = 20sin(0.5θ - 2) + 40 models the monthly temp for a certain city.
Use the equation to predict the temperature in the city during December. Thanks
assuming θ is the month, just plug in θ=12.
Come on back if you don't like the answer.
Still don't get it, so yes need more help.
Did you make sure your calculator was set to Radians ?
(press DRG until you see RAD displayed)
Here are my keystrokes
.5
x
12
-
2
=
sin
=
x
20
+
40
=
and you should get 24.86°
(Of course you can see that since sin(????) ranges from -1 to +1, the temperature must range from a minimum of 20 to a maximum of 60, so hoping the units are Fahrenheit and not Celsius
Sounds like rather dismal place to be )
To predict the temperature in the city during December using the given equation y = 20sin(0.5θ - 2) + 40, we need to substitute the value of θ (in this case, the month of December) into the equation. In the equation, θ represents the angle in radians, which corresponds to the month of the year on a unit circle.
To determine the angle for December, we need to assign values to each month of the year. Let's assign January to 0 radians, February to π/6 radians, March to 2π/6 radians, and so on. Since December is the twelfth month, it corresponds to 11π/6 radians.
Now we substitute the value of θ into the equation:
y = 20sin(0.5(11π/6) - 2) + 40
Using the value of π ≈ 3.14, we can calculate the temperature in the city during December by evaluating this equation.