How many moles of carbon are needed to react with 525 g of hematite
2FeO3+6C->4Fe+3Co2
idk how to convert moles of fe2o3 to carbon
Looks like the equation ought to be
Fe2O3 + C -> Fe + CO2
Now, we have 3 oxygens and we need 6:
2Fe2O3 + C -> 2Fe + 3CO2
Now we need to balance the carbons:
2Fe2O3 + 3C -> 2Fe + 3CO2
Looks like 3 moles of C for 2 moles of Fe2O3. Just figure out how many moles you have and multiply by 3/2.
To convert moles of Fe2O3 to moles of carbon, we need to use the balanced equation:
2FeO3 + 6C -> 4Fe + 3CO2
From the equation, we can see that 2 moles of Fe2O3 react with 6 moles of carbon. This ratio allows us to set up a conversion factor.
1 mole of Fe2O3 is equivalent to 3 moles of carbon. This can be obtained by dividing both sides of the equation by 2:
(2FeO3) / 2 = (6C) / 2
FeO3 = 3C
So, for every 1 mole of Fe2O3, we need 3 moles of carbon.
Now, let's calculate the moles of carbon needed to react with 525 g of Fe2O3.
Step 1: Determine the molar mass of Fe2O3 and carbon.
Molar mass of Fe2O3 = (2 x molar mass of Fe) + (3 x molar mass of O)
= (2 x 55.85 g/mol) + (3 x 16.00 g/mol)
= 159.70 g/mol
Molar mass of carbon = 12.01 g/mol
Step 2: Convert the given mass of Fe2O3 to moles.
Moles of Fe2O3 = mass of Fe2O3 / molar mass of Fe2O3
= 525 g / 159.70 g/mol
= 3.2848 mol
Step 3: Convert moles of Fe2O3 to moles of carbon using the conversion factor.
Moles of carbon = Moles of Fe2O3 x (3 moles of C / 1 mole of Fe2O3)
= 3.2848 mol x (3 mol C / 1 mol Fe2O3)
= 9.8544 mol
Therefore, approximately 9.8544 moles of carbon are needed to react with 525 g of Fe2O3.
To convert moles of Fe2O3 to carbon, we need to use the balanced chemical equation that relates the two substances. In this case, the balanced equation is:
2FeO3 + 6C -> 4Fe + 3CO2
First, we need to calculate the number of moles of Fe2O3. To do this, we'll use the molar mass of Fe2O3 (iron (III) oxide). The molar mass of Fe2O3 can be calculated by adding the atomic masses of each element:
Fe: 55.845 g/mol
O: 16.00 g/mol (there are 3 oxygen atoms)
Molar mass of Fe2O3:
Fe2O3 = (2 * 55.845) + (3 * 16.00) = 159.69 g/mol
Next, we'll convert the given mass of Fe2O3 (525 g) to moles using the molar mass:
Moles of Fe2O3 = mass of Fe2O3 / molar mass of Fe2O3
Moles of Fe2O3 = 525 g / 159.69 g/mol ≈ 3.286 moles
Now, using the balanced chemical equation, we can determine the mole ratio between Fe2O3 and C. From the equation, we see that 6 moles of C react with 2 moles of Fe2O3. So, the ratio is:
6 moles C / 2 moles Fe2O3 = 3 moles C / 1 mole Fe2O3
Finally, we can calculate the number of moles of C needed:
Moles of C = Moles of Fe2O3 * (3 moles C / 1 mole Fe2O3)
Moles of C = 3.286 moles * (3 moles C / 1 mole Fe2O3) ≈ 9.858 moles
Therefore, approximately 9.858 moles of carbon are needed to react with 525 g of hematite (Fe2O3) according to the balanced chemical equation.
Oops.
2Fe2O3 + 3C -> 4Fe + 3CO2