2x^2+4x-5
Rewrite quadratic function in standard form.
f(x) = 2(x^2+2x) - 5
= 2(x^2+2x+1) - 5 + 2(1)
= 2(x+1)^2 - 3
To rewrite the quadratic function 2x^2 + 4x - 5 in standard form, we need to arrange the terms in descending order of the exponent, with no like terms remaining.
The standard form of a quadratic equation is ax^2 + bx + c, where a, b, and c are constants.
Given the quadratic function 2x^2 + 4x - 5, we can rearrange the terms as:
2x^2 + 4x - 5
This is already in standard form since the terms are arranged in descending order of the exponent. Therefore, the quadratic function 2x^2 + 4x - 5 is already in standard form.
To rewrite the quadratic function in standard form, you need to arrange the terms in descending order of the degree of x. The standard form of a quadratic function is given by:
f(x) = ax^2 + bx + c
In this case, the quadratic function is:
f(x) = 2x^2 + 4x - 5
To rearrange it in standard form, let's start by arranging the terms in descending order of x:
f(x) = 2x^2 + 4x - 5 (original equation)
f(x) = 2x^2 + 4x - 5 (no change)
Now the quadratic function is already in standard form. The coefficient of x^2 is 2, the coefficient of x is 4, and the constant term is -5. So the standard form of the quadratic function is:
f(x) = 2x^2 + 4x - 5