Write linear equation in form y=mx+b given this condition parallel to y=-1/2x +1, through (4,2)?
you have a point and a slope, so the line is
y-2 = -1/2 (x-4)
To find the equation of a line parallel to y = -(1/2)x + 1 and passing through (4, 2), we can use the fact that parallel lines have the same slope.
The given line has a slope of -1/2, so the slope of the line we are looking for will also be -1/2.
Let's use the point-slope form of a linear equation: y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope.
Plugging in the values:
y - 2 = (-1/2)(x - 4)
Now, we can simplify this equation:
y - 2 = (-1/2)x + 2
y = (-1/2)x + 4
Therefore, the equation of the line parallel to y = -(1/2)x + 1 and passing through (4, 2) is y = (-1/2)x + 4, which is the linear equation in the form y = mx + b.