What is the momentum of a wavelength= 0.015nm X-ray photon?
p= in kg*m/s
Please help I am confused. Thank you.
Thank you :)
To calculate the momentum (p) of a photon, you can use the formula:
p = (h/λ) * c
Where:
p is the momentum of the photon,
h is Planck's constant (6.626 x 10^-34 J·s),
λ is the wavelength of the photon,
c is the speed of light in a vacuum (3.0 x 10^8 m/s).
Given that the wavelength (λ) of the X-ray photon is 0.015 nm, we need to convert it to meters:
1 nm = 1 x 10^-9 m
So, the wavelength in meters (λ) is:
λ = 0.015 nm * (1 x 10^-9 m/nm) = 1.5 x 10^-11 m
Now, we can substitute the values into the formula to find the momentum:
p = (6.626 x 10^-34 J·s) / (1.5 x 10^-11 m) * (3.0 x 10^8 m/s)
After performing the calculation, the momentum comes out to be:
p ≈ 0.0882 kg·m/s
Therefore, the momentum of a 0.015 nm X-ray photon is approximately 0.0882 kg·m/s.
Photon momentum is
p = h*(frequency)/c
= [h*c/(wavelength)]/c
= h/(wavelength)
where h is Planck's constant
web.utk.edu/~cnattras/Phys250Fall2012/modules/module%201/photons.htm