how do u set up with problem
How would you prepare 165 mL of a 0.0317 m solution of benzoic acid (C7H6O2) in chloroform (CHCl3)?
Just follow the definition of molarity.
M = mols per L of solution
I am assuming the m is molarity. But if it is molality, then molality is mols per kilogram of solvent.
To prepare the solution, you need to calculate the amount of benzoic acid (C7H6O2) and chloroform (CHCl3) required.
Step 1: Calculate the number of moles of benzoic acid (C7H6O2) required.
To do this, use the formula:
Moles of solute = molarity × volume in liters
Given:
Molarity (M) = 0.0317 mol/L
Volume = 165 mL = 0.165 L
Moles of benzoic acid = 0.0317 mol/L × 0.165 L
Step 2: Calculate the mass of benzoic acid (C7H6O2) required.
To find the mass, use the formula:
Mass = Moles of solute × molar mass
The molar mass of benzoic acid (C7H6O2) is:
(7 × atomic mass of carbon) + (6 × atomic mass of hydrogen) + (2 × atomic mass of oxygen)
= (7 × 12.01 g/mol) + (6 × 1.01 g/mol) + (2 × 16.00 g/mol)
Mass of benzoic acid = Moles of benzoic acid × molar mass
Step 3: Calculate the volume of chloroform (CHCl3) required.
To make a solution with a final volume of 165 mL, you need to add chloroform to the calculated mass of benzoic acid.
Ensure that you are using a weighing boat or container that can hold both the benzoic acid and the chloroform.
This method assumes the density of chloroform (CHCl3) is 1.49 g/mL.
Step 4: Calculate the mass of chloroform (CHCl3) required.
To calculate the mass of chloroform, use the formula:
Mass = Density × Volume
Given:
Density of chloroform = 1.49 g/mL
Volume of chloroform = 0.165 L
Mass of chloroform = Density of chloroform × Volume of chloroform
Finally, you would mix the calculated mass of benzoic acid and the calculated mass of chloroform together to prepare a 165 mL, 0.0317 molar solution of benzoic acid in chloroform.