Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 236 miles in the same time that Dana travels 224 miles. If Chucks rate of travel is 3 mph more than Danas, and they travel the same length of time, at what speed does Chuck travel?
Dana's speed --- x mph
Chuck's speed ---- x+3 mph
224/x = 236/(x+3)
236x = 224x + 672
12x = 672
x = 56
Dana --- 56 mph
Chuck -- 59 mph
To determine Chuck's speed, let's say Dana's speed is x mph (since Chuck's speed is 3 mph more).
We know that distance = speed * time. Since they travel the same length of time, we can set up the following equation:
236 = (x + 3) * t
224 = x * t
Since they travel the same length of time, we can equate the two expressions for time:
(x + 3) * t = x * t
Now, we can solve for t by canceling out the t terms:
x + 3 = x
Next, we can subtract x from both sides of the equation:
3 = 0
Uh-oh! We have reached a contradiction. This means our initial assumption that Dana's speed is x mph is incorrect.
There might be an error in the problem statement, because it's currently not possible to determine Chuck's speed based on the provided information.