A metal block of mass 5kg lies on a rough horizontal platform.If a horizontal force of 8N applied to the block through its centre of mass just slides the block on the platform,then the coefficient of limiting friction between the block and the platform is
0.16
Hyp*hyp=opp*opp+adj*adj
=0.16
To find the coefficient of limiting friction between the block and the platform, we need to determine the maximum force of friction that can be exerted on the block before it starts to slide.
The formula for the force of friction is given by:
F friction = μ * F normal
Where:
- F friction is the force of friction
- μ is the coefficient of friction
- F normal is the normal force acting on the block
In this scenario, the horizontal force of 8N applied to the block is equal to the force of friction required to overcome the limiting friction. Therefore:
F friction = 8N
We also know that the weight of the block, which is equal to the force of gravity acting on it, is given by:
F gravity = m * g
Where:
- F gravity is the force of gravity (weight)
- m is the mass of the block
- g is the acceleration due to gravity (approximately 9.8 m/s^2)
So, in this case:
F gravity = 5kg * 9.8 m/s^2
= 49N
The normal force acting on the block is equal to the force of gravity because the block is on a horizontal platform. Therefore:
F normal = 49N
Now we can substitute the given values into the equation F friction = μ * F normal:
8N = μ * 49N
Now we can solve for μ:
μ = 8N / 49N
≈ 0.1633
Therefore, the coefficient of limiting friction between the block and the platform is approximately 0.1633.