What volume of a 6.0 M NaOH solution would you need to prepare 250.0 milliliters of a 3.0 M NaOH solution?
Use c1v1 = c2v2
c= concn
v = volume
To solve this problem, we can use the dilution formula:
(C1)(V1) = (C2)(V2),
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Let's plug in the given values:
C1 = 6.0 M (initial concentration of the NaOH solution)
V1 = ? (initial volume of the NaOH solution)
C2 = 3.0 M (final concentration of the NaOH solution)
V2 = 250.0 mL (final volume of the NaOH solution)
Since we want to find the volume of the 6.0 M NaOH solution (V1), we rearrange the formula as follows:
V1 = (C2)(V2) / C1
Now, substitute the given values into the formula:
V1 = (3.0 M)(250.0 mL) / 6.0 M
To find the volume, we need to calculate:
V1 = (3.0 * 250.0) / 6.0 = 125.0 mL
Therefore, you would need to take 125.0 milliliters of the 6.0 M NaOH solution to prepare 250.0 milliliters of a 3.0 M NaOH solution.