In order to open tha clam it catches, a seagull will drop the clam repeatedly onto a hard surface from high in the air until the shell cracks.
if a seagull flies to a height of 16.4m, how long will the clam take to fall? The acceleration of gravity is 9.8m/s². Answer in units of sec.
To calculate the time it takes for the clam to fall from a height of 16.4m, we can use the equation of motion for free fall:
d = (1/2) * g * t^2
Where:
d = distance (16.4m in this case)
g = acceleration due to gravity (9.8m/s²)
t = time
To solve for time, we rearrange the equation to isolate t:
t^2 = (2 * d) / g
Substituting the given values, we have:
t^2 = (2 * 16.4m) / 9.8m/s²
t^2 = 33.6m / 9.8m/s²
t^2 ≈ 3.43s²
To find the value of t, we take the square root of both sides:
t ≈ √3.43s²
t ≈ 1.85s
Therefore, it will take approximately 1.85 seconds for the clam to fall from a height of 16.4m.