required to heat 38.0 g of copper (cu) from 122 degree celsius to 246 degree celsius
what requirement? heat? I suppose so.
q = mass Cu x specific heat Cu x (Tfinal-Tinitial)
To calculate the energy required to heat a substance, we can use the formula:
q = m × C × ΔT
where:
q = heat energy (in joules),
m = mass of the substance (in grams),
C = specific heat capacity of the substance (in J/g°C), and
ΔT = change in temperature (in °C).
For copper, the specific heat capacity is approximately 0.385 J/g°C.
Given:
m = 38.0 g (mass of copper),
ΔT = 246°C - 122°C = 124°C (change in temperature), and
C = 0.385 J/g°C (specific heat capacity of copper).
Applying the formula:
q = 38.0 g × 0.385 J/g°C × 124°C
Calculating the energy required:
q = 1829.6 J
Therefore, the energy required to heat 38.0 g of copper from 122°C to 246°C is approximately 1829.6 joules (J).
To calculate the energy required to heat a substance, you can use the formula:
Q = m × c × ΔT
Where:
Q is the energy required (in Joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g·°C), and
ΔT is the change in temperature (in °C).
For copper (Cu), the specific heat capacity is approximately 0.39 J/g·°C.
Given:
Mass (m) = 38.0 g
Initial temperature (T1) = 122 °C
Final temperature (T2) = 246 °C
First, calculate the change in temperature (ΔT) using the formula:
ΔT = T2 - T1
ΔT = 246 °C - 122 °C = 124 °C
Now, substitute the values into the formula:
Q = 38.0 g × 0.39 J/g·°C × 124 °C
Q ≈ 1837 Joules
Therefore, approximately 1837 Joules of energy would be required to heat 38.0 g of copper from 122 °C to 246 °C.