Simplifying y^2 + 3 + 3(y^2+1)
My answer is 4y^2+6 but the program I am using (Hawkes learning system) says it isnt correct. Any help would be greatly appreciated. I have even used several online calculators to verify and this is the answer they all come up with too. HELP
Your answer is correct.
you are correct.
Better submit a bug report on the software.
To simplify the expression y^2 + 3 + 3(y^2 + 1), you need to follow the rules of algebraic simplification. Let's break it down step by step:
1. Start by distributing the 3 to the terms inside the parentheses: 3(y^2 + 1) becomes 3y^2 + 3.
Now, the expression becomes: y^2 + 3 + 3y^2 + 3.
2. Next, group the like terms together. In this case, the like terms are the ones with the same exponent on y. So, y^2 and 3y^2 are like terms, as they both have a y^2 term.
The expression can now be simplified to: (y^2 + 3y^2) + 3 + 3.
3. Combine the like terms: y^2 + 3y^2 is equal to 4y^2. Therefore, the expression becomes: 4y^2 + 3 + 3.
4. Combine the constant terms: 3 + 3 is equal to 6.
So, the final simplified expression is: 4y^2 + 6.
According to the explanation provided, your answer of 4y^2 + 6 is correct. If the program you're using is stating otherwise, there might be a technical issue or a specific formatting requirement. Double-check the instructions or contact the support team for further assistance.