Log7x=log7 4+log7 3 please help I can not anderstand thanks
If log 7 mean logarithm to base b = 7 then :
log 7 ( x ) = log 7 ( 4 ) + log 7 ( 3 )
log ( a ) + log ( b ) = log ( a * b )
log 7 ( 4 ) + log 7 ( 3 ) = log 7 ( 4 * 3 ) = log 7 ( 12 )
log 7 ( x ) = log 7 ( 12 )
x = 12
Thank you !!:)
4.8450
To solve the equation log7x = log74 + log73, you can use the properties of logarithms.
First, remember the product rule of logarithms, which states that loga (b * c) = loga b + loga c.
Using this rule, we can rewrite the equation as:
log7x = log7 (4 * 3)
Since the bases of the logarithms are the same (log base 7), we can remove the logarithm on both sides. This means that the equation simplifies to:
x = 4 * 3
Simplifying further, we find that:
x = 12
Therefore, the solution to the equation log7x = log74 + log73 is x = 12.