a trapezoid has an area of 5 1/2 feet squared. if the trapezoid has a base that measures 2 2/3 feet and a height of 1 1/2 feet. what is the length of the other base?
A = (B+b)/2 * h
plug in your values:
11/2 = (8/3 + b)/2 * 3/2
b = 14/3 = 4 2/3
What is the area of 15 cm 2cm 6cm and 7 cm
To find the length of the other base of the trapezoid, we can use the formula for the area of a trapezoid:
Area = (1/2) * (base1 + base2) * height
In this case, we are given the area, base1, and height. Let's substitute these values into the formula and solve for base2.
5 1/2 = (1/2) * (2 2/3 + base2) * 1 1/2
First, we need to simplify the fractions:
Convert 2 2/3 to an improper fraction:
2 * 3 + 2 = 8/3
Convert 1 1/2 to an improper fraction:
1 * 2 + 1 = 3/2
Now let's substitute the values back into the equation:
5 1/2 = (1/2) * (8/3 + base2) * 3/2
Next, let's simplify the equation by multiplying the fractions:
11/2 = (1/2) * (8/3 + base2) * 3/2
Now, let's simplify the equation further by canceling out common factors:
11/2 = (1/2) * (8/3) + (1/2) * base2
11/2 = 4/3 + (1/2) * base2
To isolate base2, let's subtract 4/3 from both sides of the equation:
11/2 - 4/3 = (1/2) * base2
Now, let's find the common denominator and subtract the fractions:
(33/6) - (8/6) = (1/2) * base2
25/6 = (1/2) * base2
To find the value of base2, we need to multiply both sides by 2:
2 * (25/6) = base2
50/6 = base2
Finally, let's simplify the fraction:
base2 = 25/3
Therefore, the length of the other base of the trapezoid is 25/3 feet or approximately 8 1/3 feet.