If barometric pressure is 480mmhg, what is the partial pressure of 02 in inspired air? At this pressure, what % of 02 would you have to gave in the air you are breathing so that the inspired p02 would be normal? ( 160 mmhg)

To determine the partial pressure of oxygen (PO2) in inspired air, we need to know the percentage of oxygen in the air. The air we breathe typically contains about 21% oxygen.

Step 1: Calculate the partial pressure of oxygen (PO2) in inspired air:
PO2 = barometric pressure * percentage of oxygen
PO2 = 480 mmHg * 0.21
PO2 = 100.8 mmHg

Therefore, the partial pressure of oxygen in inspired air is approximately 100.8 mmHg.

Step 2: Calculate the percentage of oxygen required in the air you're breathing so that the inspired PO2 is normal (160 mmHg):
percentage of oxygen = PO2 required / barometric pressure
percentage of oxygen = 160 mmHg / 480 mmHg
percentage of oxygen = 0.3333

To convert this into a percentage, simply multiply by 100:
percentage of oxygen = 0.3333 * 100
percentage of oxygen = 33.33%

Therefore, you would need to have at least 33.33% of oxygen in the air you are breathing to maintain a normal inspired PO2 of 160 mmHg.

To calculate the partial pressure of O2 in inspired air, we need to use the Dalton's Law of Partial Pressures, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas.

1. First, we need to find the partial pressure of O2 in inspired air. The inspired air consists of approximately 21% oxygen.

Partial pressure of O2 = Total pressure (barometric pressure) * Fraction of O2 in the mixture

Given:
Total pressure (barometric pressure) = 480 mmHg
Fraction of O2 in the mixture = 21% = 0.21

Partial pressure of O2 = 480 mmHg * 0.21
Partial pressure of O2 = 100.8 mmHg

Therefore, the partial pressure of O2 in inspired air would be approximately 100.8 mmHg.

2. Now, let's calculate the percentage of O2 you would need to have in the air you are breathing so that the inspired partial pressure of O2 would be normal (160 mmHg).

Percentage of O2 = (Partial pressure of O2 / Normal inspired partial pressure of O2) * 100

Given:
Partial pressure of O2 = 100.8 mmHg
Normal inspired partial pressure of O2 = 160 mmHg

Percentage of O2 = (100.8 mmHg / 160 mmHg) * 100
Percentage of O2 = 63%

Therefore, you would need to have approximately 63% of O2 in the air you are breathing to maintain a normal inspired partial pressure of O2.