1\ Acar is moving with acceleration 200 m in 50 sec reached to velocity 10 m\sec .what the total distance the car moved in 60 sec
Let me get this straight:
the car, STARTING at vi
vf=vi+at
10=vi+50a
and
distance=vi*t+1/2 a t^2
200=50vi+1/2 a (2500)
two equations, two unknowns. From the first, Vi=10-50a, put that into the second,
200=50(10-50a)+ 1250a
200=500-2500a+1250a
-300=-1250a
a= 3/12.5 m/s^2 and vi=10-50a, so you have vi, a.
Now figure distance in 60 seconds