A potter's wheel rotates with an angular frequency of 1.54 rad/s. What is its period?
period=1/f=2PI/w
the speed of sound in air is 343 m/s. using the relationship: 5280 feet in a mile, 3 feet in a yard and 3.3 feet in a meter. how many meters is this?
To find the period of the potter's wheel, we can use the formula:
Period (T) = 2π / Angular Frequency (ω)
Given that the angular frequency is 1.54 rad/s, we can substitute this value into the formula:
T = 2π / 1.54
To calculate the value of T, divide 2π (approximately 6.28) by 1.54:
T ≈ 4.084 seconds
Therefore, the period of the potter's wheel is approximately 4.084 seconds.