Write the ratios for sin A and cos A.
{picture is of a right triangle, ABC.
segment AC is 8, segment AB is 17, and segment
CB is 15.}
sin A=15/17, cos A=8/17
sin A=15/8, cos A=8/17
sin A=15/17, cos A=8/15
sin A=8/17, cos A=15/17
The first is correct
for what values of 0 ,in degrees,is sin 0 = cos 58
The correct ratios for sin A and cos A are:
sin A=15/17, cos A=8/17
To find the ratios for sin A and cos A, we need to use the values of the sides of the right triangle. Let's look at the given right triangle with sides AC = 8, AB = 17, and CB = 15.
First, let's find sin A. Sin A is the ratio of the length of the side opposite to angle A (CB) to the length of the hypotenuse (AB). So, sin A = CB/AB = 15/17.
Next, let's find cos A. Cos A is the ratio of the length of the side adjacent to angle A (AC) to the length of the hypotenuse (AB). So, cos A = AC/AB = 8/17.
Therefore, the correct ratios are:
sin A = 15/17
cos A = 8/17.