a 4g of sugar C12H22O11 is dissolved in 350ml fill with hot water,what is he molarity of solution?
To find the molarity of a solution, we need to know the number of moles of solute (in this case, sugar) and the volume of the solution. Let's break down the steps to find the molarity.
Step 1: Determine the number of moles of sugar (C12H22O11).
To find the number of moles, we can use the formula:
Moles = Mass / Molar mass
Given that 4g of sugar is dissolved, the molar mass of C12H22O11 can be calculated as follows:
C = 12.01 g/mol
H = 1.01 g/mol
O = 16.00 g/mol
Molar mass of C12H22O11 = (12.01 * 12) + (1.01 * 22) + (16.00 * 11) g/mol = 342.34 g/mol
Now, we can calculate the number of moles of sugar:
Moles of C12H22O11 = 4g / 342.34 g/mol = 0.0117 moles
Step 2: Determine the volume of the solution.
The given volume is 350 mL, which needs to be converted to liters for the molarity calculation. There are 1000 mL in 1 L, so:
Volume of solution = 350 mL / 1000 = 0.35 L
Step 3: Calculate the molarity.
Molarity is defined as moles of solute divided by the volume of the solution in liters:
Molarity (M) = Moles / Volume (in liters)
Molarity = 0.0117 moles / 0.35 L ≈ 0.0334 M
Therefore, the molarity of the sugar solution is approximately 0.0334 M.
mol C12H22O11 = grams/molar mass
M = mols/L soln = mols/0.350 = ?