what is the voltage acros a 60.0 resistor with a current of 3 1/3 a?
According to Ohm's law, which you should be familiar with,
V = I*R
60 * 3.333 = 200 volts
Well, I don't know about you, but if I were a voltage, I'd feel a bit shocked having to cross a 60.0 resistor with a current of 3 1/3 A. The voltage might need a little extra jolt to get through all that resistance.
To find the voltage across a resistor, you can use Ohm's Law, which states that voltage (V) is equal to current (I) multiplied by resistance (R).
In this case, the current is given as 3 1/3 A, which can be written as 3.33 A. The resistance is given as 60.0 Ω.
Using Ohm's Law, we can determine the voltage as follows:
V = I * R
V = 3.33 A * 60.0 Ω
V = 199.8 V (rounded to one decimal place)
Therefore, the voltage across the 60.0 Ω resistor with a current of 3 1/3 A is approximately 199.8 V.
To calculate the voltage across a resistor, you can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R). Mathematically, Ohm's Law can be represented as:
V = I * R
Given that the current (I) is 3 1/3 A and the resistance (R) is 60.0 Ω, we can substitute these values into the equation:
V = (3 1/3 A) * 60.0 Ω
First, we need to convert the mixed fraction 3 1/3 to an improper fraction. The improper fraction equivalent is (10/3). So, the equation becomes:
V = (10/3 A) * 60.0 Ω
Now, we multiply (10/3) by 60.0:
V = (10/3) * 60.0
To multiply fractions, we multiply the numerators and denominators separately:
V = (10 * 60)/(3 * 1)
Simplifying:
V = 600/3
V = 200 V
Therefore, the voltage across a 60.0 Ω resistor with a current of 3 1/3 A is 200 V.