last of the homework packet questions hopefully!
These questions are the ones I had the most trouble on. I have a feeling I didn't do them correctly. :(
3. Given 325 ml of saturated gas at 760 mmHg and 25°C, what would be its volume if dry at the same pressure and temperature?
(760)(325)(298)/(736.2)(298)= 355.50ml
4. Given 2,110 ml of saturated gas at 754 mmHg and 20°C, what would be its volume saturated at 764 mmHg and 37°C?
(2110)(736.5)(310)/(716.9)(293)=2293.45ml
Problem 1 I understand.
P1 = 760 wet or 760-23.8 = 736.2 mm dry.
V1 = 325 mL wet
T1 = 298
P2 = 760 mm (adjusting to new pressure).
V2 = ??
T2 = 298 (same T).
I think you reversed P1 and P2. Other than that the answer is ok.
Problem #2 I don't understand. IF WE adjust the volume (V2) for changes in T and P ( and make no changes in pressure because we want the gas to stay wet), then we have the following.
P1 = 754 mm wet (P of water vapor is 17.5 mm Hg but I haven't subtracted it since the problem states satruated gas).
V1 = 2110 mL
T1 = 293 K
P2 = 764 mm wet
V2 = ??
T2 = 310
and solve for V2. However, and this is the part I don't understand, since the problem specifically asks for the volume saturated at 764 and 37 C, the volume I have calculated above will be the volume adjusted for both pressure and temperature BUT it will NOT be saturated at 37. The water, as calculated above, will be the amount present at 20 C and that will NOT saturate the gas at 37. My guess is that the problem actually wants what I have calculated above. You can check this out if you have an answer sheet.