The perimeter of a rectangle is 110cm. The length is 1cm more than twice the width. Write 2 equations that would be used to solve the system.
Eq1: 2L + 2W = 110.
Eq2: L = 2W+1
2(2W+1) + 2W = 110.
To solve the system of equations, let's denote the width of the rectangle as "w" and the length as "l". We are given two pieces of information:
1. The perimeter of the rectangle is 110cm, which is calculated by adding up all four sides of the rectangle: 2w + 2l = 110.
2. The length is 1cm more than twice the width: l = 2w + 1.
Thus, we can write the two equations that would be used to solve the system as:
Equation 1: 2w + 2l = 110
Equation 2: l = 2w + 1
By solving these two equations simultaneously, we can find the values of width (w) and length (l) of the rectangle.