If a = 12, b = 30, and c = 22, find the area of to the nearest tenth.
If you want find the area of a triangle then :
Area = sqrt[ s * ( s - a ) * ( s - b ) * ( s - c )]
where :
s=(a+b+c)/2
is the semi-perimeter.
s = ( 12 + 30 + 22 ) / 2
s = 64 / 2
s = 32
A = sqrt[ s * ( s - a ) * ( s - b ) * ( s - c )]
A = sqrt[ 32 * ( 32 - 12 ) * ( 32 - 30 ) * ( 32 - 22 )]
A = sqrt ( 32 * 20 * 2 * 10 )
A = sqrt ( 12800 )
A = 113.137
A = 113.1
to the nearest tenth