An urn contains 5 red marbles, 4 blue marbles, and 3 green marbles. A marble is selected at random and then, without replacing the first marble, a second marble is selected at random. What is the probability of selecting a green marble and then a red marble?
Green = 3/12
Red = 5/11, because one green marble has already been picked.
The probability of both/all events occurring if found by multiplying the probabilities of the individual events.
Solve this problem.
A bag contains 5 red marbles, 7 green marbles, and 3 orange marbles. Find the probability of drawing a red marble.
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the answer is 4
To find the probability of selecting a green marble and then a red marble, we need to consider two events happening in sequence: the first event is selecting a green marble, and the second event is selecting a red marble without replacing the first marble.
Step 1: Determine the total number of marbles in the urn. In this case, there are 5 red marbles, 4 blue marbles, and 3 green marbles, resulting in a total of 12 marbles.
Step 2: Calculate the probability of selecting a green marble as the first event. Since there are 3 green marbles out of a total of 12 marbles, the probability of selecting a green marble is 3/12, which can be simplified to 1/4.
Step 3: Calculate the probability of selecting a red marble as the second event. After selecting a green marble, we now have 11 marbles remaining in the urn, including 5 red marbles. Therefore, the probability of selecting a red marble is 5/11.
Step 4: Determine the probability of both events occurring. To find the probability of two independent events happening in sequence, you multiply their individual probabilities. So, the probability of selecting a green marble and then a red marble is (1/4) * (5/11), which equals 5/44.
Therefore, the probability of selecting a green marble and then a red marble is 5/44.