Determine the equation of the inverese of the quadratic function
f(x)=x^2-4x+3
x = y^2 - 4y + 3
y^2 - 4y = x-3
y^2 - 4 y + 4 = x+1
(y-2)^2 = x+1
y = 2 +/- sqrt(x+1)
f(x)=x^2-4x+3
y^2 - 4y = x-3
y^2 - 4 y + 4 = x+1
(y-2)^2 = x+1
y = 2 +/- sqrt(x+1)