to heat 12.4g of water from 20.0 degrees celsius to 25.0 degrees celsius requires ?
a. 259 J
b. 1300 J
c. 040 J
d. 1050 J
To calculate the amount of heat required to heat a substance, you can use the formula:
q = m * c * ΔT
where:
q is the amount of heat (in Joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g·°C), and
ΔT is the change in temperature (in °C).
In this case, the mass of the water is 12.4 grams, the specific heat capacity of water is approximately 4.18 J/g·°C, and the change in temperature is 25.0°C - 20.0°C = 5.0°C.
So, plugging in the values:
q = 12.4 g * 4.18 J/g·°C * 5.0°C
q = 259.4 J
Therefore, the amount of heat required to heat 12.4g of water from 20.0°C to 25.0°C is approximately 259 J.
So, the correct answer is a. 259 J.
To calculate the amount of heat required to raise the temperature of a substance, you can use the formula:
q = mcΔT
Where:
q is the heat energy (in joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in joules/gram °C)
ΔT is the change in temperature (in °C)
First, you need to determine the mass of water (m) and the specific heat capacity of water (c).
Given:
Mass of water (m) = 12.4g
Change in temperature (ΔT) = 25.0°C - 20.0°C = 5.0°C
The specific heat capacity of water is approximately 4.18 J/g°C.
Now, substitute the values into the formula:
q = (12.4g)(4.18 J/g°C)(5.0°C)
q = 259 J
Therefore, the amount of heat required to heat 12.4g of water from 20.0 degrees Celsius to 25.0 degrees Celsius is 259 J.
So, the correct answer is a. 259 J.