a ball is rolled up q constant slope with an initial velocity of 2.2m/s after 2 seconds the ball is rolling down the slope with a velocity of 1.1 m/s what is the acceleration of the ball
To find the acceleration of the ball, we can use the equation of motion:
v = u + at
where:
- v is the final velocity of the ball (1.1 m/s)
- u is the initial velocity of the ball (2.2 m/s)
- a is the acceleration of the ball
- t is the time taken for the ball to change velocity (2 seconds)
Rearranging the equation, we get:
a = (v - u) / t
Substituting the given values, we have:
a = (1.1 m/s - 2.2 m/s) / 2 s
Calculating the numerator:
1.1 m/s - 2.2 m/s = -1.1 m/s
Now, substitute the value back into the equation:
a = (-1.1 m/s) / 2 s
Calculating the division:
a = -0.55 m/s^2
The acceleration of the ball is -0.55 m/s^2. The negative sign indicates that the ball is decelerating or slowing down.