Kinematic--v = v0 + at and Energy--½mv2 = mgh. Solve both equations for v.
Time was 00.6
Measured from 2ft.
What is the Velocity in m/s kinematic and the Velocity in ft/s energy
To solve both equations for v, we will start with the formula for Kinematics:
v = v0 + at
Given:
v0 = initial velocity (not provided in the question)
a = acceleration (not provided in the question)
t = time = 0.6 seconds
Since the values for v0 and a are not given, we cannot determine the actual velocity using the Kinematics equation in this case.
Moving on to the Energy equation:
1/2 mv^2 = mgh
Given:
m = mass (not provided in the question)
g = acceleration due to gravity = 9.8 m/s^2
h = height = 2 ft (which needs to be converted to meters)
First, let's convert the height from feet to meters. We know that 1 meter is approximately 3.281 feet, so:
h = 2 ft * (1 meter / 3.281 feet) ≈ 0.6096 meters
Now, we can rewrite the equation as:
1/2 mv^2 = mgh
1/2 v^2 = gh
v^2 = 2gh
v = √(2gh)
Plugging in the known values:
v = √(2 * 9.8 m/s^2 * 0.6096 meters)
v ≈ √12.036 m^2/s^2
v ≈ 3.47 m/s
So, the velocity in m/s calculated using the Energy equation is approximately 3.47 m/s.
To find the velocity in ft/s using the Energy equation, we need to convert from m/s to ft/s.
1 m/s is approximately 3.281 ft/s, so:
Velocity in ft/s ≈ Velocity in m/s * (3.281 ft/s / 1 m/s)
Velocity in ft/s ≈ 3.47 m/s * 3.281 ft/s ≈ 11.38 ft/s
Therefore, the velocity in ft/s calculated using the Energy equation is approximately 11.38 ft/s.