Two employees are painting wall. A takes twice as long as B to paint the same area. During a typical 8-hour day, A works the full 8 hours, but B takes a 2-hour break. A paints one way in a day.
How many walls do both employees paint together?
I need an explanation on how to set up the problem, please?
<<A paints one way in a day. >>
Which way is that?
Is "way" supposed to be "wall"?
<<How many walls do both employees paint together? >>
In how many days?
Sorry.
It's supposed to be wall and how many walls they can paint in 1 day.
A paints one wall a day. You said that already.
B, who is twice as fast, could paint two walls in an (eight hour) day, but he only works six hours. Therefore B paints 1.5 walls in an eight hour day.
Together that paint 2.5 walls per day.
To set up this problem, we need to determine the rates at which A and B paint the walls. Let's denote the rate at which A paints as R_A (walls per hour) and the rate at which B paints as R_B (walls per hour).
We are given that A takes twice as long as B to paint the same area. This means that A's painting rate is half of B's painting rate, or R_A = (1/2)R_B.
During an 8-hour day, A works the full 8 hours, while B takes a 2-hour break. So, B works for only 8 - 2 = 6 hours.
Now, let's calculate the number of walls painted by each employee in an hour:
- A paints at a rate of R_A walls per hour.
- B paints at a rate of R_B walls per hour.
Therefore, in one hour A paints R_A walls, and in 6 hours B paints 6 * R_B walls.
Now, we need to determine the total number of walls painted by both employees during the 8-hour workday. Since A works for the entire 8 hours, A paints 8 * R_A walls in total.
Therefore, the total number of walls painted by both employees together is:
8 * R_A + 6 * R_B.
To find this value, we need to know either the specific values of R_A and R_B or obtain additional information to determine their values.