sif xyz=0 (-3x^2yz)^3 p=27x^7y^4z^6 then p=?
p can be anything, since x y z = 0 means that your equation reduces to
0*p = 0
To find the value of p, we can use the given equation and the value of xyz being 0.
We are given the equation: xyz = 0. This means that one of the variables x, y, or z is equal to 0.
Now, let's substitute the value of xyz = 0 into the second equation p = 27x^7y^4z^6:
p = 27x^7y^4z^6
Since xyz = 0, we can replace xyz with 0 in the equation:
p = 27(0)^7y^4z^6
Any number raised to the power of 0 is 1. Therefore, (0)^7 = 0.
This simplifies the equation further:
p = 27(0)y^4z^6
p = 0 * y^4z^6
p = 0
Hence, the value of p is 0 when xyz = 0.