What pressure (atm) is exerted by a column of ethanol 86.0 cm high. The density of ethanol is 0.789 g/cm3 and 9.8 m/s2 as your gravitational constant.
pressure = density*acceleration gravity*height.
0.789g/cc x 86 cm x 980 cm/s^2 =?? Pa. Divide by 1000 to convert to kPa and divide by 101.325 to convert to atm.
Read here.
http://hyperphysics.phy-astr.gsu.edu/hbase/pflu.html#fpc
To find the pressure exerted by a column of ethanol, you need to use the equation:
Pressure = Density * Gravitational constant * Height
First, let's convert the height from centimeters to meters:
86.0 cm = 0.86 m
Next, we can substitute the given values into the equation:
Pressure = 0.789 g/cm^3 * 9.8 m/s^2 * 0.86 m
To ensure consistent units, let's convert the density from grams per cubic centimeter to kilograms per cubic meter:
0.789 g/cm^3 = 789 kg/m^3 (since 1 g/cm^3 = 1000 kg/m^3)
Now we can calculate the pressure:
Pressure = 789 kg/m^3 * 9.8 m/s^2 * 0.86 m
Using a calculator, we find:
Pressure ≈ 6719.432 Pa
Since 1 atm = 101325 Pa, we can convert to atm:
Pressure ≈ 6719.432 Pa / 101325 Pa
Pressure ≈ 0.0662 atm
Therefore, the pressure exerted by the column of ethanol is approximately 0.0662 atm.