A concave mirror is constructed so that a man at a distance of 26 from the mirror sees his image magnified 1.5 times. What is the radius of curvature of the mirror?

3. A concave shaving mirror is construction so that a man at a distance of 20cm from the mirror sees his image magnified 1.5 times. What is the radius of curvature of the mirror?

nothing here

writing is like rain, you make it pour

To find the radius of curvature of the concave mirror, you can use the mirror formula, which states:

1/f = 1/v - 1/u,

where f is the focal length of the mirror, v is the image distance, and u is the object distance.

In this case, the man sees his image magnified 1.5 times, which means the magnification (m) is 1.5. The magnification is given by:

m = -v/u,

where the negative sign indicates that the image is virtual and magnified. Rearranging the equation, we have:

v/u = -m.

Substituting the given values, we get:

v/u = -1.5.

Now, we know that the object distance (u) is the distance of the man from the mirror, which is given as 26 cm. Let's substitute this value into the equation:

v/26 = -1.5.

To solve for v, we can multiply both sides of the equation by 26:

v = -1.5 * 26.

Calculating, we find that v is equal to -39 cm.

Now that we have the values for v and u, we can substitute them into the mirror formula:

1/f = 1/v - 1/u,

1/f = 1/-39 - 1/26.

Simplifying,

1/f = (-26 - 39) / (-39 * 26).

1/f = -65 / (-1014).

Now, take the reciprocal of both sides of the equation to solve for f:

f = -1014 / -65.

Calculating, we find that f is equal to approximately 15.6 cm.

The radius of curvature (R) of a concave mirror is twice the focal length (R = 2f). Therefore, the radius of curvature of the mirror is approximately 31.2 cm.