a^-5a-36=0
can anyone help me on this??
a^-5a-36=0
a^(-5a)=36
1/(a^5a)=36
1=(a^5)*36 Divide with 36
1/36=a^5
a=(1/36)^(1/5)
a=2.04767
THANK YOU
Certainly! I can help you with this equation: a^-5a - 36 = 0. To solve this equation, we need to isolate the variable "a".
Step 1: Start by adding 36 to both sides of the equation to get rid of the constant term on the left side:
a^-5a = 36
Step 2: Now, we can remove the negative exponent by taking the reciprocal of both sides of the equation:
1/(a^5) = 36
Step 3: Next, let's get rid of the fraction by taking the reciprocal of both sides again:
a^5 = 1/36
Step 4: Finally, to solve for "a", we need to take the fifth root of both sides. The fifth root of a number is the same as raising the number to the power of 1/5:
a = (1/36)^(1/5)
To calculate this value, plug in 1/36 into a calculator and raise it to the power of 1/5.
Alternatively, you can express 1/36 as a decimal, then calculate its fifth root. The final solution for "a" will be the same.
I hope this explanation helps you understand how to solve the equation! Let me know if you have any further questions.