idk how 2 do it
the teacher told us how but didn't show us
plz help
(the 2 is an exponent)
3b^2+b-10=0
Bella, please don't switch names,
do it the same way I showed you when you posted as Angel.
http://www.jiskha.com/display.cgi?id=1300932790
In google type:
"quadratic equation online"
When you see list of results click on:
Free Online Quadratic Equation Solver.Solve by Quadratic Formula
When page be open in rectacangle type:
3b^2+b-10=0
and click option solve it
You will see solution step-by-step
To solve the quadratic equation 3b^2 + b - 10 = 0, you can use the quadratic formula:
b = (-b ± √(b^2 - 4ac)) / 2a
Here, a = 3, b = 1, and c = -10. Let's substitute these values into the quadratic formula:
b = (-(1) ± √((1)^2 - 4(3)(-10))) / (2(3))
Simplifying further:
b = (-1 ± √(1 + 120)) / 6
b = (-1 ± √121) / 6
Now, let's find the roots of the equation by evaluating the two cases:
Case 1: Taking the positive square root:
b1 = (-1 + √121) / 6
b1 = (10 + 11) / 6
b1 = 21 / 6
b1 = 3.5
Case 2: Taking the negative square root:
b2 = (-1 - √121) / 6
b2 = (10 - 11) / 6
b2 = -1 / 6
b2 ≈ -0.1667
Therefore, the solutions to the equation 3b^2 + b - 10 = 0 are b = 3.5 and b ≈ -0.1667.