How do I find the slope of the line tangent to the graph of each function at the given points?
y=x^2+2x-8
dy/dx = slope = 2x + 2
at your given point, use the given x
Now although you did not ask, to find the equation of that tangent line use that slope as m in
y = m x + b
then put in the x and y of the given point on the curve to solve for b