Calculate the concentration, in molarity, of a solutiion prepared by adding 9 mL of water to 1mL of 0.1 M of HCl
You are diluting it ten times.
New concentration: .01 M
Final conc=(Initial volm 1.0mL*initial conc 0.1M)/(Final volm 10mL)= 0.01M
Ans=0.01M
To calculate the concentration in molarity (M) of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).
In this case, you are starting with 0.1 M HCl and adding water to make a solution.
Step 1: Calculate the amount of HCl in moles.
To do this, you need to use the equation:
moles = concentration (M) * volume (L)
Given that the initial volume of HCl is 1 mL and the concentration is 0.1 M, you can convert the volume to liters by dividing by 1000:
Volume = 1 mL / 1000 = 0.001 L
Then, you can calculate the number of moles of HCl using the formula:
moles of HCl = 0.1 M * 0.001 L = 0.0001 moles
Step 2: Calculate the final volume of the solution.
You started with 1 mL of HCl and added 9 mL of water. The total volume of the solution is therefore 1 mL + 9 mL = 10 mL = 0.01 L.
Step 3: Calculate the concentration of the solution.
The concentration of the solution can be calculated using the formula:
concentration (M) = moles / volume (L)
In this case, you have 0.0001 moles of HCl and a final volume of 0.01 L:
concentration (M) = 0.0001 moles / 0.01 L = 0.01 M
Therefore, the concentration, in molarity, of the solution prepared by adding 9 mL of water to 1 mL of 0.1 M HCl is 0.01 M.