find the distance between the two points(7,3)(1,5)and(8,2),(4,1)
d=sqroot[(x2-x1)^2+(y2-y1)^2]
Distance between points(7,3)(1,5)
x1=7 x2=1 y1=3 y2=5
d=sqroot[(1-7)^2+(5-3)^2]
d=sqroot[(-6)^2+2^2]
d=sqroot(36+4)
d=sqroot(40)
Distance between points(8,2)(4,1)
x1=8 x2=4 y1=2 y2=1
d=sqroot[(8-4)^2+(1-2)^2]
d=sqroot[(4)^2+(-1)^2]
d=sqroot(16+1)
d=sqroot(17)
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sqroot(40)=sqroot(4*10)=2*sqroot(10)
To find the distance between two points in a two-dimensional plane, we can use the distance formula. The formula is:
Distance = √[(x2 - x1)^2 + (y2 - y1)^2]
Let's find the distance between the points (7, 3) and (1, 5).
x1 = 7
y1 = 3
x2 = 1
y2 = 5
Now we can substitute these values into the formula:
Distance = √[(1 - 7)^2 + (5 - 3)^2]
= √[(-6)^2 + (2)^2]
= √[36 + 4]
= √40
= 2√10
So, the distance between the points (7, 3) and (1, 5) is 2√10.
Now let's find the distance between the points (8, 2) and (4, 1) using the same formula.
x1 = 8
y1 = 2
x2 = 4
y2 = 1
Distance = √[(4 - 8)^2 + (1 - 2)^2]
= √[(-4)^2 + (-1)^2]
= √[16 + 1]
= √17
So, the distance between the points (8, 2) and (4, 1) is √17.