0.238 M glucose (C6H12O6) in water (Assume the density of the solution is 1.00 g/mL.)
And your question is?
0.238 M glucose (C6H12O6) in water (Assume the density of the solution is 1.00 g/mL.)
a)0.238 M glucose (C6H12O6) in water (Assume the density of the solution is 1.00 g/mL.)
Still no question. See your post above.
To determine the mass of glucose in the solution, we need to calculate the mass of glucose and the mass of water separately and then add them together.
First, let's calculate the mass of glucose. We are given the concentration of glucose as 0.238 M, which means there are 0.238 moles of glucose per liter of solution.
The molecular weight of glucose (C6H12O6) can be calculated by adding the atomic weights of its constituent elements:
C = 12.01 g/mol
H = 1.008 g/mol
O = 16.00 g/mol
So the molecular weight of glucose is 12.01 * 6 + 1.008 * 12 + 16.00 * 6 = 180.18 g/mol.
To find the mass of glucose in the solution, we can multiply the number of moles by the molecular weight:
Mass of glucose = 0.238 mol * 180.18 g/mol = 42.90 g.
Next, let's calculate the mass of water. We are not provided with the volume of the solution, but we can assume that the density of the solution is 1.00 g/mL. Therefore, the mass of water is equal to the volume of water.
Since the density is given in grams per milliliter, the mass of water is equal to the volume of water in milliliters:
Mass of water = 1.00 g/mL * volume of water (in mL).
Finally, to find the total mass of the solution, we need to add the mass of glucose and the mass of water together:
Total mass of the solution = Mass of glucose + Mass of water.
Please provide the volume of the solution in milliliters, and we can calculate the mass of water and the total mass of the solution for you.