this december your brother jack will be 2 years from being twice as old as your sister Jen. the sum of jacks age and three times jens age is 68. how old is jen?
Jack's age=2*(Jen's age)-2
[Jack's age]+3*(Jen's age)=68
use substitution method:
[2*(Jen's age)-2]+3*(Jen's age)=68
Solve for Jen's age.
how to solve a matrice when it's like b21 and it givec you to sets of matrices like AND IT SAYS TO ID EACH ELEMENT
A.)O -1 B.)6 -3 1/2
1.5 3 AND
7 -2
Jen's age = X yrs.
Jack's age = (2X -2) YRS.
(2X - 2) + 3X = 68,
2X + 3X -2 = 68,
5X = 68 + 2 = 70,
X = 14 yrs. = Jen's age.
To solve this problem, we can set up a system of equations using the given information.
Let's start by assuming Jen's age to be x years.
According to the first piece of information, in December, Jack will be 2 years from being twice as old as Jen. This can be represented as:
Jack's age = 2(Jen's age) + 2
According to the second piece of information, the sum of Jack's age and three times Jen's age is 68. This can be represented as:
Jack's age + 3(Jen's age) = 68
Now, we can substitute the value for Jack's age from the first equation into the second equation:
(2(Jen's age) + 2) + 3(Jen's age) = 68
Simplifying the equation further:
2Jen's age + 2 + 3Jen's age = 68
Combine like terms:
5Jen's age + 2 = 68
Subtract 2 from both sides:
5Jen's age = 66
Divide both sides by 5:
Jen's age = 66 / 5
Jen's age is approximately 13.2 years.
Therefore, Jen is approximately 13.2 years old.