Triangle ABC is an isosceles triangle, where angle B is the vertex angle. If BC = 10x-4 , AC= 2x+18 , and AB= 6x+32, find the value of x.
which 2 sides are congruent? if you tell me i can easily figure it out for you...
AB = BC
6X + 32 = 10 X - 4,
6X - 10X = - 4 - 32,
-4X = -36,
X = -36 / -4 = 9.
AB = BC
6X + 32 = 10X - 4,
6X - 10X = -4 -32,
-4X = -36,
X = -36 / -4 = 9.
To find the value of x, we can use the fact that an isosceles triangle has two congruent sides. In this case, we know that AB = BC.
So, we can set up an equation by equating these two sides:
6x+32 = 10x-4
To solve for x, let's simplify the equation:
6x - 10x = -4 - 32
-4x = -36
Now, to isolate x, let's divide both sides of the equation by -4:
x = (-36) / (-4)
x = 9
Therefore, the value of x is 9.