a gas has a pressure of 1.1 atm occupies a volume of 24 liters. What will the pressure be if the gas has a final volume of 19 liters at constant temperature?
P1V1 = P2V2
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's Law is expressed as P1V1 = P2V2, where P1 and V1 represent the initial pressure and volume, and P2 and V2 represent the final pressure and volume.
Given:
Initial pressure (P1) = 1.1 atm
Initial volume (V1) = 24 liters
Final volume (V2) = 19 liters
We need to find the final pressure (P2).
Using Boyle's Law, we can rewrite the equation as:
P1V1 = P2V2
Substituting the given values:
(1.1 atm) (24 L) = P2 (19 L)
Now we can solve for P2:
P2 = (1.1 atm) (24 L) / (19 L)
P2 = 1.386 atm
Therefore, the final pressure of the gas will be approximately 1.386 atm when the volume is reduced to 19 liters at a constant temperature.