you have 4 blue crayons, 2 red and 3 orange, what is the probablity of pulling a red crayon and then an orange without replacement?
2/9 * 3/8 = ?
To find the probability of pulling a red crayon and then an orange crayon without replacement, we need to consider the total number of outcomes and the favorable outcomes.
Step 1: Calculate the total number of outcomes:
We have a total of 4 blue crayons, 2 red crayons, and 3 orange crayons. Therefore, the total number of crayons is 4 + 2 + 3 = 9.
Step 2: Calculate the number of favorable outcomes:
For the first pick, we want to select one of the 2 red crayons. After successfully picking a red crayon, we are left with 8 crayons in total (since we didn't replace the crayon). Out of these, we want to select one of the 3 orange crayons.
So, the number of favorable outcomes is: 2 (red crayons) * 3 (orange crayons) = 6.
Step 3: Calculate the probability:
The probability is given by the ratio: Favorable outcomes / Total outcomes.
Probability = 6 / 9 = 2 / 3
Therefore, the probability of pulling a red crayon and then an orange crayon without replacement is 2/3.