1. A single mole of AgNo3 weighs 169.88 grams. In order to make a 1M solution, how many grams of AgNo3 would need to be dissolved in 5oomL?
How many moles do you need?
moles = M x L.
please help today
M = moles/L
So you want 0.5 L and 1 M, you will need 1 x 0.5 = 0.5 mole.
How many grams is that?
moles = g/molar mass
To determine how many grams of AgNO3 would be needed to make a 1M solution in 500mL, we need to follow these steps:
1. Calculate the number of moles needed:
As given, we need to make a 1M (1 molar) solution. Moles can be calculated using the formula: Moles = Molarity (M) x Volume (L).
Given that the volume is 0.500 L (converted mL to L), the equation becomes: Moles = 1 M x 0.500 L = 0.500 moles.
2. Convert moles to grams:
We know that the molar mass of AgNO3 is 169.88 grams/mol. To convert the moles of AgNO3 to grams, we use the formula: Grams = Moles x Molar mass.
Plugging in the values, we have: Grams = 0.500 moles x 169.88 grams/mol = 84.94 grams.
Therefore, to make a 1M solution in 500mL, you would need to dissolve 84.94 grams of AgNO3.