How many moles of solute are contained in a 150ml solution of a 0.25 M NaNO3 solution?
M = mol/L
mol = ML
.0375 = .25 M * .15 L
.038 mol (2 sig digit)
moles = M x L
To determine the number of moles of solute in a solution, you can use the formula:
moles of solute = Molarity × Volume (in liters)
In this case, you have a 150 mL solution with a molarity of 0.25 M NaNO3. To solve this, you need to convert the volume from milliliters to liters.
Step 1: Convert the volume from milliliters to liters:
150 mL ÷ 1000 = 0.150 L
Step 2: Apply the formula to calculate the number of moles of solute:
moles of solute = 0.25 M × 0.150 L
moles of solute = 0.0375 moles
Therefore, there are 0.0375 moles of NaNO3 solute in a 150 mL solution of 0.25 M NaNO3.