How would i solve this problem?(It's on a MathCounts worksheet and i don't understand it)
the ^ mean exponents
-(1^2008)+(-1)^2007
the first parenthesis, one to any power is 1. The second is -1 to an odd power, which is -1
-1-1=
can you find a problem for me plesea
the length is 10 inches, the height is 4 inches,and the width is 8 inches. How many cubic inches of soil does the plant hold. (hint V=LWH
1. byd=c
2. 4by=T
3. b=xyc
4. 12xyt=36R
1. byd=c
2. 4by=T
3. b=xyc
4. 12xyt=36R
To solve this problem, you need to understand the order of operations and the properties of exponents.
Let's break down the given expression step by step.
Step 1: Simplify the first term -(1^2008).
The expression inside the parentheses (1^2008) means that 1 is raised to the power of 2008. Any number raised to the power of 0 is 1, so 1^2008 is equal to 1.
Since the first term has a negative sign in front of it, the expression becomes -(1). Therefore, the first term simplifies to -1.
Step 2: Simplify the second term (-1)^2007.
Here, we have (-1) raised to the power of 2007. Remember that any odd power of -1 is -1, and any even power of -1 is 1.
Since 2007 is an odd number, (-1)^2007 simplifies to -1.
Step 3: Combine the simplified terms from Step 1 and Step 2.
We have -1 + (-1) = -2.
Therefore, the solution to the given expression -(1^2008) + (-1)^2007 is -2.
It's important to understand the properties of exponents and to apply the order of operations correctly when solving math problems.