During a swing the head of a golf club is in contact with the ball for about 0.5 ms and the ball goes from zero to 69 m/s. Assuming the acceleration is constant, determine its value.
Use the definition of acceleration.
Divide the velocity change by the time interval.
140000 m/s squared
To determine the acceleration, we can use the kinematic equation that relates acceleration, time, and final velocity:
v = u + at
Where:
v = final velocity (69 m/s)
u = initial velocity (0 m/s)
a = acceleration (unknown)
t = time (0.5 ms = 0.5 × 10^(-3) s)
Rearranging the equation to solve for acceleration (a), we have:
a = (v - u) / t
Substituting the given values:
a = (69 m/s - 0 m/s) / (0.5 × 10^(-3) s)
Now let's calculate:
a = 69 m/s / (0.5 × 10^(-3) s)
a = 69 m/s / (0.0005 s)
a = 138,000 m/s^2
Therefore, the acceleration of the golf ball is 138,000 m/s^2.