Calculate the weight of KHP that will react with 25mL of .1M NaOH
25 mL x 0.1 M NaOH = M x L = moles. Solve for moles.
moles KHP = moles NaOH.
moles KHP = grams/molar mass
Solve for grams.
15
To calculate the weight of KHP (potassium hydrogen phthalate) that will react with 25mL of 0.1M (moles per liter) NaOH (sodium hydroxide), you need to use the concept of stoichiometry and the balanced chemical equation of the reaction between KHP and NaOH.
The balanced chemical equation for the reaction is:
KHP + NaOH → NaKP + H2O
From the balanced equation, you can see that the stoichiometric ratio between KHP and NaOH is 1:1. This means that 1 mole of KHP will react with 1 mole of NaOH.
Now, let's determine the number of moles of NaOH in 25mL of 0.1M NaOH:
First, convert the volume from milliliters to liters:
25mL = 25/1000 = 0.025L
Now, use the formula:
Moles = Volume (L) x Concentration (M)
Moles of NaOH = 0.025L x 0.1M = 0.0025 moles
Since the stoichiometric ratio between KHP and NaOH is 1:1, the number of moles of KHP required will be the same as the number of moles of NaOH.
Hence, to calculate the weight of KHP, you need to know the molar mass of KHP.
The molar mass of KHP is 204.23 g/mol.
Weight of KHP (g) = Moles x Molar mass of KHP
Weight of KHP = 0.0025 moles x 204.23 g/mol
Weight of KHP = 0.511 g (rounded to three decimal places)
Therefore, the weight of KHP that will react with 25mL of 0.1M NaOH is approximately 0.511 grams.